Answer
$135$ cm$^3$, or (F)
Work Step by Step
We know that the length of the side of the base is $9$, which is $4$ more than the height.
Height $= x = 9-4 = 5$.
With $x$ known, we can plug in to find the volume:
$V(5) = \frac{1}{3}(x^3+8x^2+16x) \\ = \frac{1}{3}(5^3 + 8*5^2+16*5) = 135$
