Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

End-of-Course Assessment - Page 967: 32

Answer

$160$ km, or (H)

Work Step by Step

Go by the formula: $d = rt$, meaning distance = rate*time. We have two steps with the same distance d, so the total distance is $d+d = 2d$. Each step has two different rates $r_1, r_2$ that take two different times $t_1, t_2$ $t_1 = 4, t_2 = 10$ If trip 2 is upstream of a 6 km/h current that trip 1 is downstream of, $r_1 = r_2 + 12$ Solve for the rates by setting the distances equal $d_1 = d_2$, $r_1t_1 = r_2t_2$, $(r_2+12)*4 = r_2*10, \ 4r_2+48 = 10r_2, 6r_2 = 48, r_2 = 8$ $r_1 = r_2+12 = 8+12 = 20$ $d_tot = d_1+d_2 = r_1t_1 + r_2t_2 = 20*4 + 8*10 = 160$
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