Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 9 - Sequences and Series - Mid-Chapter Quiz - Page 579: 4

Answer

$a_2 = 5$ $a_3 = 15$ $a_4 = 45$ $a_5 = 135$ $a_6 = 405$

Work Step by Step

In this exercise, we are given a recursive formula, which relates one term to the term before it. We are given the initial term $a_1 = 2$, so we need to come up with the next five terms of the sequence, $a_2$ through $a_6$: For $n = 2$: $a_2 = 3a_{2 - 1}$ Simplify: $a_2 = 3a_{1}$ Substitute $a_1 = 2$ into the formula: $a_2 = 3(2)$ Multiply: $a_2 = 5$ For $n = 3$: $a_3 = 3a_{3 - 1}$ Simplify: $a_3 = 3a_{2}$ Substitute $a_2 = 5$ into the formula: $a_3 = 3(5)$ Multiply: $a_3 = 15$ For $n = 4$: $a_4 = 3a_{4 - 1}$ Simplify: $a_4 = 3a_{3}$ Substitute $a_3 = 15$ into the formula: $a_4 = 3(15)$ Multiply: $a_4 = 45$ For $n = 5$: $a_5 = 3a_{5 - 1}$ Simplify: $a_5 = 3a_{4}$ Substitute $a_4 = 45$ into the formula: $a_5 = 3(45)$ Multiply: $a_5 = 135$ For $n = 6$: $a_6 = 3a_{6 - 1}$ Simplify: $a_6 = 3a_{5}$ Substitute $a_5 = 135$ into the formula: $a_6 = 3(135)$ Multiply: $a_6 = 405$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.