Algebra 2 Common Core

f(1)=3$\frac{1}{3}$ f(2)=7$\frac{1}{3}$ f(3)=11$\frac{1}{3}$ f(4)=15$\frac{1}{3}$
f(x)=4x-$\frac{2}{3}$ f(1)=4(1)-$\frac{2}{3}$ =3$\frac{1}{3}$ f(2)=4(2)-$\frac{2}{3}$ =7$\frac{1}{3}$ f(3)=4(3)-$\frac{2}{3}$ =11$\frac{1}{3}$ f(4)=4(4)-$\frac{2}{3}$ =15$\frac{1}{3}$ *You just plug the new number into each of the x's in the original function and then simplify to get your answer.