Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 9 - Sequences and Series - Chapter Review - Page 606: 43

Answer

$S_8 = 53.125$

Work Step by Step

To find the sum of a finite geometric series, we can use the formula: $S_n = \frac{a_1(1 - r^n)}{1 - r}$, $r \ne 1$, where $S_n$ is the sum of the series, $n$ is the number of terms in the series, $a_1$ is the first term, and $r$ is the common ratio. We already have $a_1 = 80$ and $n = 8$; however, we need to find $r$. This can be done by setting up a ratio of the second term to the first term: $r = \frac{-40}{80} = -\frac{1}{2}$ Now that we have the common ratio, we can now plug in our values into the formula to calculate the sum of a geometric series: $S_8 = \frac{80(1 - (-\frac{1}{2})^8)}{1 - (-\frac{1}{2})}$ Evaluate exponents first: $S_8 = \frac{80(1 - \frac{1}{256})}{1 - (-\frac{1}{2})}$ Evaluate what's in parentheses: $S_8 = \frac{80(\frac{255}{256})}{1 + \frac{1}{2}}$ Add: $S_8 = \frac{80(\frac{255}{256})}{\frac{3}{2}}$ Multiply next: $S_8 = \frac{\frac{20,400}{256}}{\frac{3}{2}}$ Divide fractions by multiplying the numerator by the reciprocal of the denominator: $S_8 = \frac{20,400}{256} \times \frac{2}{3}$ Multiply: $S_8 = \frac{40,800}{768}$ Simplify: $S_8 = 53.125$
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