Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 9 - Sequences and Series - 9-4 Arithmetic Series - Practice and Problem-Solving Exercises - Page 591: 9

Answer

$S_{8} = 92$

Work Step by Step

To find the sum of a finite series, we can use the formula: $S_n = \frac{n}{2}(a_1 + a_n)$, where $S_n$ is the sum of the series, $n$ is the number of terms in the series, $a_1$ is the first term, and $a_n$ is $nth$ last term. List the values we are given: $a_{1} = 8$ $a_{n} = 15$ We don't know what term the last number in the series, $15$, is, so we plug $15$ into the explicit formula for an arithmetic sequence, which will give us the number of the term $15$ in the series: $a_{n} = a_{1} + (n - 1)d$, where $a_{n}$ is a certain term in a sequence, $a_{1}$ is the first term in the sequence, $n$ is the number of the term within the sequence, and $d$ is the common difference. The common difference $d$ is found by subtracting a term from the one directly following it: $d = 9 - 8 = 1$ The common difference $d$ is $1$. Let's plug in the values we know into the explicit formula for an arithmetic sequence: $15 = 8 + (n - 1)1$ Use distributive property: $15 = 8 + n - 1$ Combine like factors on the right side of the equation: $15 = 7 + n$ Subtract $7$ from each side of the equation: $n = 8$ This means that there are $8$ terms in this finite series. Let's plug in the values that we are given into the formula to find the sum of a finite arithmetic series: $S_{8} = \frac{8}{2}(8 + 15)$ Simplify the fraction: $S_{8} = 4(8 + 15)$ Evaluate what's in parentheses first: $S_{8} = 4(23)$ Multiply to solve: $S_{8} = 92$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.