Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 9 - Sequences and Series - 9-1 Mathematical Patterns - Practice and Problem-Solving Exercises - Page 569: 15


Next three terms: 65, 62, and 59 Formula: $a_{1}$=80, $a_{n}$=$a_{n-1}-3$

Work Step by Step

First find the change that is consistent in the problem, by subtracting the second term with the first term, you get $-3$. You see this change with the third and second term, so on and so forth; $-3$ is a constant change. We know $a_{1}=80$, all we need now is a formula. The next term is 3 less than the previous term. Thus, the formula is: $a_{n}$=$a_{n-1}-3$ Therefore, the next three terms are: $68-3=65 \\65-3=62 \\62-3=59$
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