Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 8 - Rational Functions - Cumulative Standards Review - Multiple Choice - Page 558: 1

Answer

$C$

Work Step by Step

Factor all expressions to their simplest forms: $\dfrac{5x}{(x - 3)(x + 3)} - \dfrac{4x}{(x + 3)(x + 2)}$ The least common denominator, or LCD, incorporates all factors in the denominators of the fractions. In this case, the LCD is $(x - 3)(x + 3)(x + 2)$. Convert each fraction to an equivalent one by multiplying its numerator with whatever factor is missing between its denominator and the LCD: $\dfrac{5x(x + 2)}{(x - 3)(x + 3)(x + 2)} - \dfrac{4x(x - 3)}{(x - 3)(x + 3)(x + 2)}$ Multiply to simplify: $\dfrac{5x^2 + 10x}{(x - 3)(x + 3)(x + 2)} - \dfrac{4x^2 - 12x}{(x - 3)(x + 3)(x + 2)}$ Subtract the fractions: $$\begin{align*} \dfrac{5x^2+10x-(4x^2-12x)}{(x-3)(x+3)(x+2)}&=\dfrac{5x^2+10x-4x^2+12x}{(x-3)(x+3)(x+2)}\\ &=\dfrac{x^2 + 22x}{(x - 3)(x + 3)(x + 2)} \end{align*}$$ This answer corresponds to option $C$.
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