Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 8 - Rational Functions - Chapter Review - Page 556: 29

Answer

$\dfrac{2x - 2}{3x - 1}$

Work Step by Step

Do the subtraction in the numerator and denominator first. Find the least common denominator (LCD) of the two terms of the numerator and the two terms of the denominator: $\dfrac{\frac{2x}{x} - \frac{2}{x}}{\frac{3x}{x} - \frac{1}{x}}$ Perform the subtraction in both the numerator and the denominator: $\dfrac{\frac{2x - 2}{x}}{\frac{3x - 1}{x}}$ Use the rule $\dfrac{\frac{a}{b}}{\frac{c}{d}}=\dfrac{a}{b} \cdot \dfrac{d}{c}$: $\dfrac{2x - 2}{x} \cdot \dfrac{x}{3x - 1}$ Multiply the numerators together, and multiply the denominators together: $\dfrac{x(2x - 2)}{x(3x - 1)}$ Cancel common factors in the numerator and denominator: $\dfrac{2x - 2}{3x - 1}$
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