Answer
$\dfrac{x + 5}{x + 4}, x \ne -5, -4$
Work Step by Step
Factor both the numerator and the denominator:
$$\dfrac{(x + 5)(x + 5)}{(x + 5)(x + 4)}$$
Cancel common factor $x+5$ in the numerator and denominator:
$$\dfrac{x + 5}{x + 4}$$
Restrictions on $x$ occur when the value of $x$ makes the denominator of the original expression equal $0$ as this makes the rational expression undefined.
To find the restrictions, set each factor in the denominator equal to $0$, then solve each equation.
First factor:
$$\begin{align*}x + 5 &= 0\\
x&=-5
\end{align*}$$
Second factor:
$$\begin{align*}
x + 4 &= 0\\
x&=-4
\end{align*}$$
Therefore, the restriction is:
$$x \ne -5, -4$$
