Answer
$\log$ ${p^7q^2}$
Work Step by Step
Use the Power Property of Logarithms to rewrite this expression. The property states that $\log_b {m^n} = n \log_b {m}$. Thus, the given expression is equivalent to:
$$\log {p^7} + \log {q^{2}}$$
Use the Product Property of Logarithms. According to this property, $\log_b$ ${mn} = \log_b {m} + \log_b {n}$. Thus the expression above is equivalent to:
$$\log{p^7q^2}$$