Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 8 - Rational Functions - 8-5 Adding and Subtracting Rational Expressions - Practice and Problem-Solving Exercises - Page 541: 57

Answer

$\log$ ${p^7q^2}$

Work Step by Step

Use the Power Property of Logarithms to rewrite this expression. The property states that $\log_b {m^n} = n \log_b {m}$. Thus, the given expression is equivalent to: $$\log {p^7} + \log {q^{2}}$$ Use the Product Property of Logarithms. According to this property, $\log_b$ ${mn} = \log_b {m} + \log_b {n}$. Thus the expression above is equivalent to: $$\log{p^7q^2}$$
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