Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 8 - Rational Functions - 8-5 Adding and Subtracting Rational Expressions - Lesson Check - Page 539: 3

Answer

$\dfrac{11m}{3m + 6}$ Restriction: $m \ne -2$

Work Step by Step

Before subtracting the two expressions, we need to find the least common denominator. Let's factor the denominators completely first: $\dfrac{m}{3(m + 2)} - \dfrac{4m}{m + 2}$ The least common denominator (LCD) is $3(m + 2)$. We have to multiply each of the numerators by the factor in the LCD that is missing: $\dfrac{m}{3(m + 2)} + \dfrac{(4m)(3)}{3(m + 2)}$ Multiply out the terms to simplify: $\dfrac{m}{3m + 6} - \dfrac{12m}{3m + 6}$ Now, we subtract the numerators and keep the denominator as-is: $\dfrac{11m}{3m + 6}$ Now, we need to find the restrictions by seeing what values of the variable will make the denominator equal to zero because if the denominator of any rational expression is zero, the expression is undefined. To find the restrictions on the variable, set each factor in the denominator equal to zero: $3m + 6 = 0$ Subtract $6$ from each side: $3m = -6$ Divide both sides by $3$: $m = -2$ Restriction: $m \ne -2$
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