## Algebra 2 Common Core

$\log_{\frac{1}{2}}{8}=-3$
Recall: $$a^y=b \longleftrightarrow \log_a{b}=y$$ Use the definition above to obtain: $$8=\left(\frac{1}{2}\right)^{-3} \longrightarrow \log_{\frac{1}{2}}{8}=-3$$