Answer
$\ln{\left(\frac{1}{4}\right)}$
Work Step by Step
RECALL:
$b\cdot \ln{a}=\ln{\left(a^b\right)}$
Use the rule above to obtain:
\begin{align*}
-2\ln{2}&=\ln{\left(2^{-2}\right)}\\
&=\ln{\left(\frac{1}{2^2}\right)}\\
&=\ln{\left(\frac{1}{4}\right)}
\end{align*}