Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 7 - Exponential and Logarithmic Functions - 7-3 Logarithmic Functions as Inverses - Practice and Problem-Solving Exercises - Page 458: 97

Answer

$\dfrac{1}{4}$

Work Step by Step

Substitute $2$ to $x$ in $x^3\cdot x^5$ to obtain: \begin{align*} &=\frac{x^8}{x^{10}}\\\\ &=\frac{2^8}{2^{10}}\\\\ &=2^{8-10}\\\\ &=2^{-2}\\\\ &=\frac{1}{2^2}\\\\ &=\frac{1}{4} \end{align*}
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