Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 7 - Exponential and Logarithmic Functions - 7-3 Logarithmic Functions as Inverses - Practice and Problem-Solving Exercises - Page 457: 57

Answer

$7$

Work Step by Step

Let $y=\log{(1.3 \times 10^7)}=\log{13,000,000}$. RECALL: $y=\log{a} \longleftrightarrow 10^y=a$ Use the definition above to obtain: \begin{align*} y=\log{13,000,000} \longrightarrow 10^y=13,000,000 \end{align*} Note that: $10^{7}=10,000,000$ $10^{8}=100,000,000$ Since $10,000,000 \lt 13,000,000 \lt 100,000,000$, then $10^{7} \lt 10^y \lt 10^{8}$ Hence, $7 \lt y \lt 8$ and so $7 \lt \log{(1.3\times 10^7)} \lt 8$. Checking using a calculator gives $\log{(1.3\times 10^7)}\approx 7.1139$. Therefore, the greatest integer that is less than $\log{(1.3\times 10^7)}$ is $7$.
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