Chapter 6 - Radical Functions and Rational Exponents - Cumulative Standards Review - Multiple Choice - Page 428: 3

$C$

We see that $x^3 + 64$ is the sum of two cubes. We can factor using the formula: $(a + b)(a^2 - ab + b^2)$ We plug in the values, where $a = \sqrt[3] {x^3}$ (or $a = x$) and $b = \sqrt[3] {64}$ (or $b = 4$:): $(x + 4)(x^2 - 4x + 16) = 0$ This corresponds to option $C$.