Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-4 Rational Exponents - Lesson Check - Page 385: 5

Answer

$\sqrt[4]{11^3}$

Work Step by Step

Recall: $\sqrt[n]{x}=x^{\frac{1}{n}}$ Thus, the given expression above is equivalent to: $=\sqrt[2]{11}\sqrt[4]{11}$ $=11^{\frac{1}{2}} \cdot 11^{\frac{1}{4}}$ Recall the basic exponent property (pg. 360): $a^ma^n=a^{m+n}$ Applying this property, the expression above simplifies to: $=11^{\frac{1}{2}+\frac{1}{4}}$ $=11^{\frac{2}{4}+\frac{1}{4}}$ $=11^{\frac{3}{4}}$ Recall the basic exponent property (pg. 360): $a^{\frac{m}{n}}=\sqrt[n]{a^m}$ Applying this property, we get: $11^{\frac{3}{4}}=\sqrt[4]{11^3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.