Answer
$x = \dfrac{11}{6}$
Work Step by Step
We are asked to solve this equation using the quadratic formula, which is given by:
$x = \dfrac{-b ± \sqrt {b^2 - 4ac}}{2a}$
where $a$ is the coefficient of the first term, $b$ is the coefficient of the 1st degree term, and $c$ is the constant.
Let's plug in the numbers from our equation into the formula:
$x = \dfrac{-(-132) ± \sqrt {(-132)^2 - 4(36)(121)}}{2(36)}$
Let's simplify:
$x = \dfrac{132 ± \sqrt {17,424 - 17,424}}{72}$
Let's simplify what is inside the radical:
$x = \dfrac{132 ± \sqrt {0}}{72}$
Simplify to get rid of the radical:
$x = \dfrac{132}{72}$
Simplify the fraction by dividing both numerator and denominator by $12$:
$x = \dfrac{11}{6}$
