Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-1 Roots and Radical Expressions - Practice and Problem-Solving Exercises: 45

Answer

always true

Work Step by Step

RECALL: For any real number $a$, $\sqrt{a} \ge 0$, where $ a\ge 0$. Note that $\sqrt{x^4} = \sqrt{(x^2)^2}$ and $\sqrt{(x^2)^2} = x^2.$ Thus, the given statement is always true because $x^2$ is never negative, making it a valid value of $\sqrt{x^4}$.
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