Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-1 Roots and Radical Expressions - Practice and Problem-Solving Exercises - Page 364: 13


$-\dfrac{8}{13}$ and $\dfrac{8}{13}$

Work Step by Step

Note that $\left(\frac{8}{13}\right)^2=\frac{64}{169}$, so $\frac{8}{13}$ is a real square root of $\frac{64}{169}$, and $\left(-\frac{8}{13}\right)^2=\frac{64}{169}$, so $-\frac{8}{13}$ is a also real square root of $\frac{64}{169}$. Thus, the real square roots of $\frac{64}{169}$ are $-\frac{8}{13}$ and $\frac{8}{13}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.