Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 5 - Polynomials and Polynomial Functions - 5-9 Transforming Polynomial Functions - Practice and Problem-Solving Exercises - Page 345: 50

Answer

$y = -\frac{4}{5}x + \frac{16}{5}$

Work Step by Step

Because we are given a point on the graph along with the slope, it makes sense for us to use the point-slope form of an equation, which is given by the following formula: $y - y_1 = m(x - x_1)$ where $m$ is the slope of the graph and $(x_1, y_1)$ is a point on that graph. Substitute $m=-\frac{4}{5}, x=-1. \quad \text{and} \quad y=4$ into the point-slope form above to obtain: $y - 4 = -\frac{4}{5}[x - (-1)]$ $y - 4 = -\frac{4}{5}(x + 1)$ Distribute the right side to simplify: $y - 4 = -\frac{4}{5}x - \frac{4}{5}$ Convert this equation into the slope-intercept form by adding $4$ to each side of the equation and isolating $y$ on the left side of the equation: $y = -\frac{4}{5}x - \frac{4}{5} + 4$ $y = -\frac{4}{5}x - \frac{4}{5} + \frac{20}{5}$ $y = -\frac{4}{5}x + \frac{16}{5}$
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