Answer
$x = ± 9i$
Work Step by Step
Subtract $81$ from both sides to shift the constant to the right side of the equation:
$x^2+81-81=0-81\\
x^2 = -81$
Take the square root of both sides:
$x = \pm\sqrt {-81}\\
x = \pm\sqrt {(-1)(81)}$
The square root of $-1$ is $± i$, and the square root of $81$ is $± 9$:
$x = ± 9i$