Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 5 - Polynomials and Polynomial Functions - 5-5 Theorems About Roots of Polynomial Equations - Lesson Check - Page 315: 3

Answer

Possible rational roots: $\pm \frac{1}{3}$, $\pm \frac{2}{3}$, $\pm 1$, $\pm \frac{4}{3}$, $\pm 2$, , $\pm 3$, $\pm 4$, $\pm 6$, $\pm 12$

Work Step by Step

The coefficient of the leading term is $3$, and the constant is $-12$. Find the factors of the coefficient of the leading term and the factors of the constant term: Coefficient of the leading term factors: $\pm 1$, $\pm 3$ Constant term factors: $\pm 1$, $\pm 12$, $\pm 6$, $\pm 2$, $\pm 4$, $\pm 3$ Possible rational roots can be found using the formula: $\frac{p}{q}$, where $p$ is a factor of the constant term and $q$ is a factor of the leading coefficient. Plug factors into this formula: Possible rational roots: $\pm \frac{1}{1}$, $\pm \frac{1}{3}$, $\pm \frac{12}{1}$, $\pm \frac{12}{3}$, $\pm \frac{6}{1}$, $\pm \frac{6}{3}$, $\pm \frac{2}{1}$, $\pm \frac{2}{3}$, $\pm \frac{4}{1}$, $\pm \frac{4}{3}$, $\pm \frac{3}{1}$, $\pm \frac{3}{3}$ Simplify the fractions, leaving out duplicate roots: Possible rational roots: $\pm 1$, $\pm \frac{1}{3}$, $\pm 12$, $\pm 4$, $\pm 6$, $\pm 2$, $\pm \frac{2}{3}$, $\pm \frac{4}{3}$, $\pm 3$
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