Answer
$x^2+4x+3+\dfrac{5}{x-1}$
Work Step by Step
Using the long division method below, the given expression, $
(x^3+3x^2-x+2)\div(x-1)
,$ is equal to
\begin{align*}
x^2+4x+3+\dfrac{5}{x-1}
.\end{align*}
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