Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - Mid-Chapter Quiz - Page 224: 15

Answer

$(n-5)^2$

Work Step by Step

The given expression, $ -10n+25+n^2 ,$ is equivalent to \begin{align*} & n^2-10n+25 \\&= (n)^2-2(5n)+(5)^2 \\&= (n)^2-2(n\cdot5)+(5)^2 .\end{align*} Using $(x+y)^2=(x)^2+2(x\cdot y)+(y)^2$ or the square of a binomial, the expression above is equivalent to \begin{align*} (n-5)^2 .\end{align*}
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