Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - Chapter Test - Page 273: 6

Answer

$4i$

Work Step by Step

Use the definition of the square roots of negative numbers: $\sqrt {-16} = \sqrt {(-1)(16)}$ Use the multiplication property of square roots to rewrite the radical: $\sqrt {(-1)(16)} = \sqrt {-1} \cdot \sqrt {16}$ Use the definition of $i$ to substitute for $\sqrt {-1}$: $i \cdot \sqrt {16}$ Take the square root of $16$: $4i$
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