Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-4 Factoring Quadratic Expressions - Got It? - Page 220: 5

Answer

$(4x + 9)(4x - 9)$

Work Step by Step

This expression looks like it could be factored as the difference of two squares. Use the following steps to determine this: 1. Check to see if the first and last terms are perfect squares: Take the square root of the first term: $\sqrt {16x^2} = 4x$ Take the square root of the last term: $\sqrt {81} = 9$ 2. The formula for factoring the difference of two squares is the following: $a^2 - b^2 = (a + b)(a - b)$ In this exercise, $a = 4x$ and $b = 9$. 3. Write the expression in polynomial in factored form: $(4x + 9)(4x - 9)$
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