Answer
b = 6, c = -3
Work Step by Step
We know from standard form $(ax^2+bx+c)$ that a = -3. So we can write this in vertex form: $y=a(x−h)^2+k = -3(x-1)^2 + 0 = -3(x-1)^2$
We can expand: $-3(x^2-2x+1) = -3x^2+6x-3$, therefore, b = 6, c = -3
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