Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 3 - Linear Systems - Chapter Test - Page 187: 3

Answer

The solution is $(40, 12)$.

Work Step by Step

Substitute $y=2+0.25x$ into the first equation: $0.3x - (2 + 0.25x) = 0$ Distribute first: $0.3x - 2 - 0.25x) = 0$ Group like terms: $(0.3x - 0.25x) - 2 = 0$ Combine like terms: $0.05x - 2 = 0$ Add $2$ to each side of the equation: $0.05x = 2$ Divide each side by $0.05$ to solve for $x$: $x = 40$ Now that we have the value for $x$, we can substitute this value in for $x$ into the second equation to solve for $y$: $y = 0.25(40) + 2$ Multiply first: $y = 10 + 2$ Add to solve for $y$: $y = 12$ The solution is $(40, 12)$.
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