Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 3 - Linear Systems - Chapter Review - Page 184: 13

Answer

This system of equations has no solution.

Work Step by Step

We need to modify one equation so that one of the variables is the same in both equations but differing in sign. Let's multiply the first equation by $-2$: $-4x - 6y = -8$ Now, we set up the system of equations using the second equation and the modified equation instead of the original first one: $-4x - 6y = -8$ $4x + 6y = 9$ Combine the two equations by adding them together: $0 = 1$ This statement is false, which means that the two lines will never meet; therefore, this system of equations has no solution.
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