Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 3 - Linear Systems - 3-5 Systems With Three Variables - Practice and Problem-Solving Exercises - Page 171: 20

Answer

$(2, -1, 1)$

Work Step by Step

Label the original equations: 1. $x + 4y - 5z = -7$ 2. $3x + 2y + 3z = 7$ 3. $2x + y + 5z = 8$ The first step is to choose two equations to work with where one variable can be eliminated. Let's choose equations $2$ and $3$. Modify the equations by multiplying them by a non-zero factor so that one variable is the same in both equations but differing in sign so that this variable can be eliminated when the two equations are added together. Multiply equation $3$ by $-2$ and leave equation $2$ as-is: 2. $3x + 2y + 3z = 7$ 3. $-2(2x + y + 5z) = -2(8)$ Distribute and multiply to simplify: 2. $3x + 2y + 3z = 7$ 3. $-4x - 2y - 10z = -16$ Add the equations. This will become equation $4$: 4. $-x - 7z = -9$ Now, choose another two equations again and modify them. Modify these equations such that the $y$ variable can be eliminated. This modified equation will be equation $5$ and will be added to equation $4$ to try to eliminate another variable. Use equations $1$ and $2$. Multiply equation $2$ by $-2$ and leave equation $1$ as-is: 1. $x + 4y - 5z = -7$ 2. $-2(3x + 2y + 3z) = -2(7)$ Distribute and multiply to simplify: 1. $x + 4y - 5z = -7$ 2. $-6x - 4y - 6z = -14$ Add the equations together. This will become equation $5$: 5. $-5x - 11z = -21$ Set up a system of equations consisting of equations $4$ and $5$: 4. $-x - 7z = -9$ 5. $-5x - 11z = -21$ Modify these equations such that the $x$ variable can be eliminated. Multiply equation $4$ by $-5$ and leave equation $5$ as-is: 4. $-5(-x - 7z) = -5(-9)$ 5. $-5x - 11z = -21$ Distribute and multiply to simplify: 4. $5x + 35z = 45$ 5. $-5x - 11z = -21$ Add the two equations together: $24z = 24$ Divide both sides by $24$ to solve for $z$: $z = 1$ Substitute this value for $z$ into equation $4$ to solve for $x$: 4. $-x - 7(1) = -9$ Multiply to simplify: $-x - 7 = -9$ Add $7$ to each side of the equation to move constants to the right side of the equation: $-x = -2$ Divide both sides by $-1$ to solve for $x$: $x = 2$ Substitute the values for $x$ and $z$ into one of the original equations to find $y$. Use equation $3$: $2(2) + y + 5(1) = 8$ Multiply to simplify: $4 + y + 5 = 8$ Combine like terms on the left side of the equation: $y + 9 = 8$ Subtract $9$ from each side of the equation: $y = -1$ The solution is $(2, -1, 1)$. Check the solution by plugging in the values into one of the original equations: Equation $1$: $2 + 4(-1) - 5(1) = -7$ $2 - 4 - 5 = -7$ $-7 = -7$ Both sides are equal to one another; therefore, the solution is correct.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.