Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 3 - Linear Systems - 3-4 Linear Programming - Practice and Problem-Solving Exercises - Page 162: 37

Answer

$x$-intercept: $(1, 0)$ $y$-intercept: $(0, -1)$

Work Step by Step

This equation is in the slope-intercept form which is given by the equation: $y = mx + b$ where $m$ is the slope and $b$ is the $y$-intercept. The $y$-intercept is defined as the point on the graph when $x$ is $0$. In the equation $y = x - 1$, the $y$-intercept is $-1$; therefore, the $y$-intercept occurs at $(0, -1)$. We can find the $x$-intercept by setting $y$ equal to $0$ because the definition of the $x$-intercept is that it is the point on the graph when $y$ is $0$. Let us set $y$ equal to $0$ to find the $x$-intercept: $0 = x - 1$ $1=x$ The $x$-intercept occurs at $(1, 0)$, and the $y$-intercept occurs at $(0, -1)$.
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