Answer
$y+6=-16(x+1)$
Work Step by Step
With the given points, $
(-1,-6)$ and $(-2,10),$ then
\begin{align*}
y_1&=
-6
,\\y_2&=
10
,\\x_1&=
-1
,\text{ and }\\ x_2&=
-2
.\end{align*}
Using $m=\dfrac{y_1-y_2}{x_1-x_2}$ or the Slope Formula, the slope, $m,$ of the line connecting the two given points is
\begin{align*}
m&=
\dfrac{-6-10}{-1-(-2)}
\\\\&=
\dfrac{-6-10}{-1+2}
\\\\&=
\dfrac{-16}{1}
\\\\&=
-16
.\end{align*}
Using $
y-y_1=m(x-x_1)
$ or the Point-Slope Form, with $m=
-16
$ and using the point $
(-1,-6)
$, then
\begin{align*}
y-(-6)&=-16(x-(-1))
\\
y+6&=-16(x+1)
.\end{align*}
A Point-Slope Form of the line with the given conditions is $
y+6=-16(x+1)
.$