Answer
$m=\dfrac{2}{3}$
Work Step by Step
With the given points, $ (3,2)\text{ and } (-3,-2) ,$ then \begin{array}{l}\require{cancel} y_1= 2 ,\\y_2= -2 ,\\x_1= 3 ,\text{ and }\\ x_2= -3 .\end{array} Using $m=\dfrac{y_1-y_2}{x_1-x_2}$ or the Slope Formula, the slope, $m,$ of the line is
\begin{align*}\require{cancel}
m&=\dfrac{2-(-2)}{3-(-3)} \\\\ &=\dfrac{2+2}{3+3} \\\\ &=\dfrac{4}{6}
\\\\
&=\dfrac{\cancel4^2}{\cancel6^3}
&\text{(divide by $2$)}
\\\\&=
\dfrac{2}{3}
.\end{align*}
Hence, the slope is $
m=\dfrac{2}{3}
$.
