Answer
\begin{array}{l}\require{cancel}
\text{Slope-Intercept Form: }
y=-\dfrac{1}{2}x-\dfrac{3}{4}
\\\text{Slope: }
-\dfrac{1}{2}
\\\text{$y$-intercept: }
\left(0, -\dfrac{3}{4}\right)
\end{array}
Work Step by Step
Using the properties of equality, the given equation, $
-\dfrac{1}{2}x-y=\dfrac{3}{4}
,$ is equivalent to
\begin{array}{l}\require{cancel}
-y=\dfrac{1}{2}x+\dfrac{3}{4}
\\\\
-1(-y)=\left( \dfrac{1}{2}x+\dfrac{3}{4} \right)(-1)
\\\\
y=-\dfrac{1}{2}x-\dfrac{3}{4}
.\end{array}
Using $y=mx+b$ (where $m$ is the slope and $b$ is the $y$-intercept) or the Slope-Intercept Form of linear equations, then the equation above has the following properties
\begin{array}{l}\require{cancel}
\text{Slope-Intercept Form: }
y=-\dfrac{1}{2}x-\dfrac{3}{4}
\\\text{Slope: }
-\dfrac{1}{2}
\\\text{$y$-intercept: }
\left(0, -\dfrac{3}{4}\right)
.\end{array}