Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 2 - Functions, Equations, and Graphs - 2-3 Linear Functions and Slope-Intercept Form - Practice and Problem-Solving Exercises - Page 78: 24

Answer

\begin{array}{l}\require{cancel} \text{Slope-Intercept Form: } y=-\dfrac{1}{2}x-\dfrac{3}{4} \\\text{Slope: } -\dfrac{1}{2} \\\text{$y$-intercept: } \left(0, -\dfrac{3}{4}\right) \end{array}

Work Step by Step

Using the properties of equality, the given equation, $ -\dfrac{1}{2}x-y=\dfrac{3}{4} ,$ is equivalent to \begin{array}{l}\require{cancel} -y=\dfrac{1}{2}x+\dfrac{3}{4} \\\\ -1(-y)=\left( \dfrac{1}{2}x+\dfrac{3}{4} \right)(-1) \\\\ y=-\dfrac{1}{2}x-\dfrac{3}{4} .\end{array} Using $y=mx+b$ (where $m$ is the slope and $b$ is the $y$-intercept) or the Slope-Intercept Form of linear equations, then the equation above has the following properties \begin{array}{l}\require{cancel} \text{Slope-Intercept Form: } y=-\dfrac{1}{2}x-\dfrac{3}{4} \\\text{Slope: } -\dfrac{1}{2} \\\text{$y$-intercept: } \left(0, -\dfrac{3}{4}\right) .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.