## Algebra 2 Common Core

$-3\frac{1}{5}$, $-2$, $-1\frac{2}{5}$, and $\frac{2}{5}$.
We substitute the values in. $\frac{3}{5}(-2)-2=-\frac{6}{5}-2=-1\frac{1}{5}-2=-3\frac{1}{5}$ $\frac{3}{5}(0)-2=0-2=-2$ $\frac{3}{5}(1)-2=\frac{3}{5}-2=-1\frac{2}{5}$ $\frac{3}{5}(4)-2=\frac{12}{5}-2=2\frac{2}{5}-2=\frac{2}{5}$