## Algebra 2 Common Core

$x=0.225$
To find $x$ when $y=\frac{1}{2}$, set up a proportion using two forms of $\frac{y}{x}$ $\dfrac{\frac{5}{3}}{\frac{3}{4}}=\dfrac{\frac{1}{2}}{x}$ Now write the cross-products $(\frac{5}{3})x=(\frac{3}{4})(\frac{1}{2})$ Simplify $(\frac{5}{3})x=\frac{3}{8}$ Divide each side by $\frac{5}{3}$ $\frac{(\frac{5}{3})x}{\frac{5}{3}}=\dfrac{\frac{3}{8}}{\frac{5}{3}} \\x=\frac{3}{8} \cdot \frac{3}{5} \\x=\frac{9}{40}=0.225$