Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 2 - Functions, Equations, and Graphs - 2-2 Direct Variation - Practice and Problem-Solving Exercises - Page 71: 19

Answer

$x = -3$

Work Step by Step

First, we need to find the constant of variation for this exercise. We have an $x$ value and a $y$ value. Let's plug these values into the formula for direct variation, $y = kx$ to find $k$, the constant of variation: $4 = k(-2)$ Divide both sides by $-2$ to isolate $k$: $k = -2$ Our constant of variation is $-2$. Now, we want to find $x$ when $y$ is a specific value. We plug $y$ and the $k$ we just found into the formula for direct variation: $6 = -2x$ Divide both sides by $-2$: $x = -3$
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