## Algebra 2 Common Core

Published by Prentice Hall

# Chapter 2 - Functions, Equations, and Graphs - 2-1 Relations and Functions - Practice and Problem-Solving Exercises - Page 67: 44

#### Answer

$x=\frac{2}{3}$ $x=\frac{-20}{3}$

#### Work Step by Step

To solve an absolute value equation, we solve for $x$ using the positive and negative value of the non-absolute value side (after isolating the absolute value expression). In this case, we solve $3x+9=11$ and $3x+9=-11$. To solve $3x+9=11$, we subtract 9 from both sides to isolate $x$ and its coefficient, and then divide both sides by 3 to fully isolate $x$. $3x=2$ is $x=\frac{2}{3}$ To solve $3x+9=-11$, we subtract 9 from both sides to isolate $x$ and its coefficient and then divide both sides by 3 to fully isolate $x$. $3x=-20$ is $x=\frac{-20}{3}$

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