Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 2 - Functions, Equations, and Graphs - 2-1 Relations and Functions - Practice and Problem-Solving Exercises: 31

Answer

$V=1543.5\pi$

Work Step by Step

We substitute $10.5$ into the equation. That gives $V=\frac{4}{3}\pi (10.5)^3=\frac{4}{3}\pi\times1157.625=1543.5\pi$.
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