Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 14 - Trigonometric Identities and Equations - Get Ready! - Page 901: 2

Answer

$x=\sqrt{23},-\sqrt{23}$

Work Step by Step

$x^2-23=0$ Step 1 - we must add 23 to both sides of the equation: $x^2 = 23$ Step 2 - we must take the square root of both sides of the equation: $x=\pm\sqrt{23} \\x=\sqrt{23},-\sqrt{23}$
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