Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 14 - Trigonometric Identities and Equations - 14-5 The Law of Cosines - Practice and Problem-Solving Exercises - Page 940: 17

Answer

$x^{o} \approx 50.8^{o} $

Work Step by Step

Apply law of cosines $n^2=m^2+p^2-2 mp \cos N$ Need to solve for n. That is, $n=\sqrt {m^2+p^2-2 mp \cos N} $ Plug the given values to obtain: $a=\sqrt {(30)^2+(38)^2-2 \times 30 \times 38 \cos 50^{o}} \approx 29.6$ In order to calculate the value of $B$, we will use $M =x^{o}$. $\dfrac{\sin M}{m}=\dfrac{\sin N}{n} \implies M=\sin^{-1} (\dfrac{m \sin N}{n}) $ or, $x^{o}=\sin^{-1} (\dfrac{30 \sin 50^{o}}{29.6}) \implies x^{o} \approx 50.8^{o} $
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