## Algebra 2 Common Core

$$\tan\theta$$
Simplify $$\sin^{2}\theta\csc\theta\sec\theta.$$ Use the Reciprocal Identities $$\csc\theta=\frac{1}{\sin\theta}$$ and $$\sec\theta=\frac{1}{\cos\theta}$$ to obtain $$\sin^{2}\theta\csc\theta\sec\theta=\sin^{2}\theta\bigg(\frac{1}{\sin\theta}\bigg)\bigg(\frac{1}{\cos\theta}\bigg)=\frac{\sin\theta}{\cos\theta}=\tan\theta,$$ with the last equality based on the Tangent Identity.