Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 12 - Matrices - 12-4 Inverse Matrices and Systems - Practice and Problem-Solving Exercises - Page 797: 13

Answer

Coefficient Matrix $=\begin{bmatrix} 3 & 5 \\ 1 & 1\end{bmatrix} $; Variable Matrix $=\begin{bmatrix} a \\ b \end{bmatrix}$; and Constant Matrix $=\begin{bmatrix} 0 \\ 2\end{bmatrix}$ Our matrix equation is: $\begin{bmatrix} 3 & 5 \\ 1 & 1 \end{bmatrix} \begin{bmatrix} x \\ y\end{bmatrix} =\begin{bmatrix} 0 \\ 2 \end{bmatrix}$

Work Step by Step

Write the given system of equations into the matrix form in order to label the parts of the matrix equation. We are given the system of equations as follows: $$3a+5b=0 \\ a+b=2$$ Our matrix equation is: $\begin{bmatrix} 3 & 5 \\ 1 & 1 \end{bmatrix} \begin{bmatrix} x \\ y\end{bmatrix} =\begin{bmatrix} 0 \\ 2 \end{bmatrix}$ Our required results are: Coefficient Matrix $=\begin{bmatrix} 3 & 5 \\ 1 & 1\end{bmatrix} $; Variable Matrix $=\begin{bmatrix} a \\ b \end{bmatrix}$; and Constant Matrix $=\begin{bmatrix} 0 \\ 2\end{bmatrix}$
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