Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 12 - Matrices - 12-1 Adding and Subtracting Matrices - Practice and Problem-Solving Exercises - Page 768: 14

Answer

$ X= \begin{bmatrix} -4 & -1 \\ -1 &-2 \end{bmatrix}$

Work Step by Step

Using the properties of matrix equality, the given equation, $ X+ \begin{bmatrix} 6 & 1 \\ -2 & 3 \end{bmatrix} = \begin{bmatrix} 2 & 0 \\ -3 &1 \end{bmatrix} ,$ is equivalent to \begin{align*} X+ \begin{bmatrix} 6 & 1 \\ -2 & 3 \end{bmatrix} -\begin{bmatrix} 6 & 1 \\ -2 & 3 \end{bmatrix} &= \begin{bmatrix} 2 & 0 \\ -3 &1 \end{bmatrix} - \begin{bmatrix} 6 & 1 \\ -2 & 3 \end{bmatrix} \\\\ X &= \begin{bmatrix} 2 & 0 \\ -3 &1 \end{bmatrix} - \begin{bmatrix} 6 & 1 \\ -2 & 3 \end{bmatrix}. \\\\ X &= \begin{bmatrix} 2-6 & 0-1 \\ -3-(-2) &1-3 \end{bmatrix} \\\\ X &= \begin{bmatrix} -4 & -1 \\ -1 &-2 \end{bmatrix} .\end{align*} Hence, $ X= \begin{bmatrix} -4 & -1 \\ -1 &-2 \end{bmatrix} $.
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