## Algebra 2 Common Core

$j^{3}+9j^{2}k+27jk^{2}+27k^{3}$
Expand $(j+3k)^{3}$ using Pascal's Triangle: $(j+3k)^{3}=j^{3}+3j^{2}(3k)+3j(3k)^{2}+(3k)^{3}$. Multiply the terms: $j^{3}+9j^{2}k+27jk^{2}+27k^{3}$.