Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 11 - Probability and Statistics - Get Ready!: 9

Answer

$j^{3}+9j^{2}k+27jk^{2}+27k^{3}$

Work Step by Step

Expand $(j+3k)^{3}$ using Pascal's Triangle: $(j+3k)^{3}=j^{3}+3j^{2}(3k)+3j(3k)^{2}+(3k)^{3}$. Multiply the terms: $j^{3}+9j^{2}k+27jk^{2}+27k^{3}$.
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