Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 11 - Probability and Statistics - 11-3 Probability of Multiple Events - Practice and Problem-Solving Exercises - Page 693: 62

Answer

$\dfrac{3}{16}$

Work Step by Step

With the given spinner divided equally into $4$ colors, then each color has probability of $\dfrac{1}{4}$ from being chosen. In $2$ spins, the probability of getting not a yellow and then a green is \begin{align*}\require{cancel} P(\text{not yellow, then green})&= \dfrac{3}{4}\cdot\dfrac{1}{4} \\\\&= \dfrac{3}{16} .\end{align*} Hence, the probability of getting not a yellow and then a green in the second spin is $ \dfrac{3}{16} .$
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