Answer
$\dfrac{3}{16}$
Work Step by Step
With the given spinner divided equally into $4$ colors, then each color has probability of $\dfrac{1}{4}$ from being chosen. In $2$ spins, the probability of getting not a yellow and then a green is
\begin{align*}\require{cancel}
P(\text{not yellow, then green})&=
\dfrac{3}{4}\cdot\dfrac{1}{4}
\\\\&=
\dfrac{3}{16}
.\end{align*}
Hence, the probability of getting not a yellow and then a green in the second spin is $
\dfrac{3}{16}
.$