Answer
The vertex form: $y=2(x-1)^2+8$
Work Step by Step
The vertex form of a quadratic function is $f(x) = a(x – h)^2 + k$, where $a, h, k$ are constants. The vertex of the parabola is at $(h, k)$
By completing the square $y=2x^2-4x+10$. we get $y=2(x-1)^2+8$
Thus $a=2, h=1, k=8$, Vertex is $(1,8)$.
