Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 1 - Expressions, Equations, and Inequalities - Chapter Review - Page 52: 29

Answer

$x = -8$ or $x = -12$

Work Step by Step

Divide each side by $3$ to obtain: $$|x + 10| = 2$$ Use the definition $|x|=a \longrightarrow x=-a \quad \text{or} \quad x=a$ to obtain:: $$x + 10 = 2\quad \text{or} \quad x + 10 = -2$$ Solve the first equation first. Subtract $10$ from each side to isolate the constants to one side and the variable to the other: $$x = -8$$ Solve the other equation. We subtract $10$ from each side to isolate the constants to one side and the variable to the other: $$x = -12$$ Check for extraneous solutions. Plug $x = -8$ into the original equation: $$3|-8 + 10| = 6\\ 3|2| = 6\\ 3(2)=6\\ 6=6$$ This statement is true; therefore, $-8$ is a solution of this equation. Substitute $-12$ for $x$: $$3|-12 + 10| = 6\\ 3|-2| = 6\\ 3(2)=6 6=6$$ This statement is true; therefore, $-12$ is a solution of this equation.
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